This is a math problem I found on the net while surffing.
I thought it was intresting, and thought some of you might enjoy it.
Leave a comment with your OWN answer to the problem.
No checking previous commenters for hints, or clues. Cheater.
Story:
Three men went to a hotel to rent a room.
The cost of the room was $30.
Each man paid $10 to the bellboy and proceeded to there room.
After a little while the bellboy realized that there was a special on rooms that night and the price for the mens room should have been $25.
On his way to the mens room to give them back $5 he was puzzled how he was going to split $5 as he had no change.
He decided he would give them each $1 and keep the remaining $2 for himself.
So, each man originally paid $10, but after the bellboy gave each man $1 back, each man paid $9.
9 x 3 = $27 plus the $2 the bellboy put in his pocket equals $29.
The original price for the room was $30.
Where did the last dollar go?
Additial Information:
In the end each man paid $9, and the bellboy kept $2
I know you can reverse the problem and add the 25 with the 3 the men were refunded and the 2 the bellboy kept.
There is a reason why the problem comes up 1 dollar short and its not because you counted the $2 twice.
